0=10x^2-4x+8

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Solution for 0=10x^2-4x+8 equation: 



0=10x^2-4x+8

We move all terms to the left:

0-(10x^2-4x+8)=0

We add all the numbers together, and all the variables

-(10x^2-4x+8)=0

We get rid of parentheses

-10x^2+4x-8=0

a = -10; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-10)·(-8)
Δ = -304
Delta is less than zero, so there is no solution for the equation

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